Practice question

**Microscope principle** objective of short focal length forms real image between F_e and 2F_e of eyepiece, eyepiece magnifies to virtual image at D, total magnification product, for f_o=2 cm, f_e=5 cm, L=20 cm, m_o≈10, M_e≈6, M≈60, illustrating high magnification from two stages. In a compound microscope, the objective lens forms a real, inverted image of the object. The eyepiece then acts as a magnifying lens, forming a virtual image of this inverted intermediate image. Since the eyepiece does not reinvert the image, the final image remains inverted relative to the original object. Substituting values gives Due to the objective forming an inverted real image, which