Practice question

Given: Calculate the osmotic pressure of a solution containing 2.7 g of glucose ( C₆H₁₂O₆ ) in 250 mL of water at 27°C. ( R = 0.0821 L atm/mol K, Molar mass of glucose = 180 g/mol ) These values define the system as per NCERT data. Formula: Moles of glucose = 2.7/180 = 0.015 mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Volume = 0.25 L. Molarity = 0.015/0.25 = 0.06 M . Pi = 0.06 × 0.0821 × 300 = 1.478 atm . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.