Practice question
Question
What is the ll constant if the resistance of a conductivity ll with 0.01 M KCl solution is 200 Ω and its conductivity is 0.14 × 10â»Â² S cmâ»Â¹?
Explanation
Given:
What is the ll constant if the resistance of a conductivity ll with 0.01 M KCl solution is 200 Ω and its conductivity is 0.14 × 10â»Â² S cmâ»Â¹?
These values define the system as per NCERT data.
Formula:
Cell constant, G^* = kappa × R = 0.14 × 10â»Â² × 200 = 0.28 cm^{-1 ..
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step.
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Discussion
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