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Question

A train moving at 72km/h decelerates at 1.5m/s2 for 8s, then at 3m/s2 until it stops. What is the total distance covered during deceleration?

Options

Choose one · Correct answer highlighted

Explanation

Speed: 72km/h=20m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 20 m/s as the result, so option A is correct.