Practice question
Question
A stationary wave on a string fixed at both ends has a frequency of 150 Hz and a wave speed of 45 m/s. What is the wavelength?
Explanation
Given:
A stationary wave on a string fixed at both ends has a frequency of 150 Hz and a wave speed of 45 m/s. What is the wavelength?
These values define the system as per NCERT data.
Formula:
Wavelength: lambda = v/v = 45/150 = 0.3 m ..
This is standard NCERT relation.
Substitution & Calculation:
Substituting values and simplifying step by step as per NCERT method.
Result:
The computed value matches expected outcome and confirms correct choice as per NCERT.
Discussion
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