Practice question

Given: A neutron ( 1 u ) at 6 × 10⁶m/s collides elastically with a deuterium ( 2 u ). What fraction of its kinetic energy is transferred? These values define the system as per NCERT data. Formula: Fraction transferred f_2 = 4 m_1 m_2/(m_1 + m_2)² = 4 × 1 × 2/(1 + 2)² = 8/9 approx 0.889 .. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.