Practice question

**Concave mirror image formation** depends on object position: beyond C real inverted diminished between F and C, at C real inverted same size at C, between C and F real inverted magnified beyond C, at F image at infinity, within F virtual erect magnified behind mirror. Focal length: f = (R/2) = (36/2) = 18 cm (convex mirror). Object distance: u = -27 cm . Mirror equation: (1/v) + (1/u) = (1/f) . (1/v) + (1/-27) = (1/18) ⇒ (1/v) = (1/18) + (1/27) = (3 + 2/54) = (5/54) . v = (54/5) = 10.8 cm (virtual image). Substituting values gives 9 cm, which