Practice question
Question
An object is placed \( 24 \, \text{cm} \) from a concave mirror of focal length \( 12 \, \text{cm} \).
What is the image distance?
Explanation
**Mirror formula** 1/f = 1/v + 1/u governs spherical mirrors, f = R/2, R radius of curvature (m), u object distance (m), v image distance (m), sign convention: distances in front of mirror negative for real is convention but magnitude used, magnification m = -v/u, concave forms real inverted when object beyond F, virtual erect within F. Focal length: f = -12 cm , u = -24 cm . Mirror equation: (1/v) + (1/-24) = (1/-12) ⇒ (1/v) = (1/-12) + (1/24) = (-2 + 1/24) = (-1/24) . v = -24 cm (real image). Substituting values gives 24 cm, which matches expected image position
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