Practice question

**Concave mirror image formation** depends on object position: beyond C real inverted diminished between F and C, at C real inverted same size at C, between C and F real inverted magnified beyond C, at F image at infinity, within F virtual erect magnified behind mirror. Focal length: f = -5 cm , u = -10 cm . Mirror equation: (1/v) + (1/-10) = (1/-5) ⇒ (1/v) = (1/-5) + (1/10) = (-2 + 1/10) = (-1/10) . v = -10 cm . Magnification: m = -(v/u) = -(-10/-10) = -1 . Image height: h' = m × h = -1 × 2 = -2