Practice question
Question
A car accelerates from 10m/s at 1.5m/s2 for 6s, then moves at constant speed for 4s. What is the average speed over the entire motion?
Explanation
Phase 1: v=10+1.5⋅6=19m/s, x1=10⋅6+12⋅1.5⋅(6)2=60+27=87m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 17 m/s as the result, so option B is correct.