Practice question
Question
A brass wire of length 1.8m and cross-sectional area 2.5×10−6m2 is stretched by a force producing a strain of 2×10−4. If the Young's modulus of brass is 9×1010N/m2, what is the stress?
Explanation
Young's modulus: Y = StressStrain. Stress: Stress = Y×Strain = 9×1010×2×10−4 = 1.8×107N/m2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.8×107N/m2. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Discussion
Comments
Share your thoughts. New comments appear after admin approval.
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.