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Practice question

MCQ

Question

A copper block of dimensions 0.4 m × 0.3 m × 0.1 m is subjected to a shearing force of 3 × 104 N. If the shear modulus of copper is 4.2 × 1010 N/m2, what is the displacement of the top face?

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Explanation

Shear modulus: G = (F / A) / (Δx / L). Rearrange: Δx = (F L) / (A G). Area: A = 0.4 × 0.3 = 0.12 m2, L = 0.1 m. Substitute: Δx = (3 × 104 × 0.1) / (0.12 × 4.2 × 1010) = 3000 / (5.04 × 109) ≈ 5.95 × 10-7 m.

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