A brass wire of length 1.8m and cross-sectional area 2.5×10−6m2 is stretched by a force producing a strain of 2×10−4. If
Young's modulus: Y = StressStrain. Stress: Stress = Y×Strain = 9×1010×2×10−4 = 1.8×107N/m2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.8×107N/m2. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.