Practice question
Question
A 0.6 M solution of NaCl (molar mass = 58.5 g/mol) has a density of 1.05 g/mL. What is the molality of the solution if 200 mL is prepared?
Explanation
Moles = 0.6 × 0.2 = 0.12 mol . Mass of NaCl = 0.12 × 58.5 = 7.02 g . Total mass = 200 × 1.05 = 210 g . Mass of water = 210 - 7.02 = 202.98 g = 0.20298 kg . Molality = (0.12/0.20298) ≈ 0.591 mol/kg .
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