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Question

What is the energy equivalent of a neutron with mass \( 1.6749 \times 10^{-27} \, \text{kg} \) in
Joules? (Given \( c = 3 \times 10^8 \, \text{m/s} \))

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Explanation

**Binding energy calculation** from mass defect, for nucleus mass number 28 BE 224 MeV BE/A=8 MeV, A=18 BE 144 MeV BE/A=8 MeV, BE/A indicates stability, fusion of light nuclei and fission of heavy release energy because product has higher BE/A, difference released. E = m c² . m = 1.6749 × 10⁻²⁷ kg , c² = (3 × 10⁸)² = 9 × 10¹⁶ m²/s² . E = 1.6749 × 10⁻²⁷ × 9 × 10¹⁶ ≈ 1.507 × 10⁻¹⁰ J . Using E_n = -13.6/n² eV, r_n = n² a₀, L = n h/2π, R = R₀ A^¹/³, BE = Δm c² and 1 u =

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