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#weight calculation

2 public questions tagged with this topic.

A body weighs 147N on Earth’s surface. What is its weight at a height h\=RE/3? (g\=9.8m/s2)

g(h) = g(1+h/RE)2. h = RE/3, 1+h/RE = 4/3. g(h) = 9.8(4/3)2 = 9.8×916 = 5.51m/s2. Mass: m = 147/9.8 = 15kg. Weight: W = 15×5.51≈82.7N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 83 N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A body weighs 343N on Earth’s surface. What is its weight at a height h\=RE/5? (g\=9.8m/s2)

g(h) = g(1+h/RE)2. h = RE/5, 1+h/RE = 1+1/5 = 6/5. g(h) = 9.8(6/5)2 = 9.8×2536 = 6.81m/s2. Mass: m = 343/9.8 = 35kg. Weight: W = 35×6.81≈238N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 238 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.