A pipe’s cross-sectional area changes from 0.1m2 to 0.025m2. If water flows at 2.2m/s in the larger section, what is the
Continuity equation: A1v1 = A2v2. A1 = 0.1m2, v1 = 2.2m/s, A2 = 0.025m2. v2 = A1v1A2 = 0.1×2.20.025 = 8.8m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 8.8 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.