How much charge (in coulombs) is required to oxidize 1 mole of H₂O to O₂? (F = 96500 C/mol)
2H₂O → O₂ + 4H⁺ + 4e⁻ . 1 mol O₂ requires 4F. Charge = 4 × 96500 = 386000 C .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Variation of Conductivity with Concentration and Measurement
