A capillary tube of radius 0.15mm is dipped in water (S\=0.0727N/m, ρ\=1000kg/m3, cosθ\=1). What is the capillary rise?
h = 2Scosθρga. S = 0.0727N/m, ρ = 1000kg/m3, g = 9.8m/s2, a = 0.15×10−3m. h = 2×0.0727×11000×9.8×0.15×10−3 = 0.0989m = 9.89cm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 9.9 cm. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.