What is the oxidation number of vanadium in VOSO₄?
Let V = x. O = -2, SO₄²⁻ = -2. In VO: x + (-2) = +2 (cation charge), x = +4. Total: +4 + (-2) = 0.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Classical and Electronic Concept of Redox and Oxidation Number