Skip to content

#tube radius

2 public questions tagged with this topic.

A capillary tube of radius 0.55mm is dipped in water (S\=0.0727N/m, ρ\=1000kg/m3, cos⁡θ\=1). What is the capillary rise?

h = 2Scos⁡θρga. S = 0.0727N/m, ρ = 1000kg/m3, g = 10m/s2, a = 0.55×10−3m. h = 2×0.0727×11000×10×0.55×10−3 = 0.02645m = 2.645cm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.7 cm. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.