A transformer has \( N_p = 200 \), \( N_s = 400 \). If \( V_p = 110 \, \text{V} \) (rms), what is the secondary voltage?
**AC generator** converts mechanical to electrical, emf e = N B A ω sin ωt, maximum e₀ = N B A ω, frequency = rotation frequency, transformer cannot work on DC because steady flux no induction, LC oscillations energy swaps between ½ L I² and ½ Q²/C at ω₀=1/√(LC). (V_s/V_p) = (N_s/N_p) . V_s = V_p × (N_s/N_p) = 110 × (400/200) = 220 V . Applying X_L = ωL, X_C = 1/ωC, Z = √(R² + (X_L - X_C)²), I_rms = V_rms/Z, P = V_rms I_rms cosφ, V_s/V_p = N_s/N_p, calculation gives 220 V, consistent with phasor analysis and resonance condition X_L = X_C.
Ref: NCERT > Physics Book > Alternating Currents > Transformer, AC Generator and LC Oscillations