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λ₀ = hc/W₀ ≈ 497 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
W₀ = hc/λ₀ ≈ 3.976×10⁻¹⁹ J. E = hc/λ ≈ 4.970×10⁻¹⁹ J. KE ≈ 9.94×10⁻²⁰ J. Vₛ = KE/e ≈ 0.621 V.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger
W₀ ≈ 4.417×10⁻¹⁹ J. E = 6.626×10⁻¹⁹ J. KE ≈ 2.209×10⁻¹⁹ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Discovery of Subatomic Particles - Electron Proton Neutron
λ₀ = hc/W₀ ≈ 443.7 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Discovery of Subatomic Particles - Electron Proton Neutron
λ₀ = hc/W₀ = 6.626×10⁻³⁴ × 3.0×10⁸ / 3.31×10⁻¹⁹ = 6.0×10⁻⁷ m = 600 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Developments Leading to Bohr Model - Electromagnetic Radiation and Spectrum
W₀ = hc/λ₀ = 3.9756×10⁻¹⁹ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
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