21 public questions tagged with this topic.
When both nitrogen and sulphur are present, they form NaSCN, which reacts with Fe³⁺ to give a blood-red color (Fe(SCN)₃).
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Isomerism - Stereoisomerism - Geometrical and Optical Isomerism
Let S = x. O = -2. Equation: 2x + 3(-2) = -2, 2x - 6 = -2, 2x = 4, x = +2 (average).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Types of Redox Reactions - Combination Decomposition Displacement
The oxidizing agent is reduced. S (0) gains electrons to become S (-2) in Na₂S, oxidizing Na (0 to +1).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
Let S = x. H = +1. Equation: 2(+1) + x = 0, 2 + x = 0, x = -2.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
Let S = x. O = -2. Equation: 2x + 3(-2) = -2, 2x - 6 = -2, 2x = 4, x = +2 (average).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
S (+4 in SO₂) remains +4 in H₂SO₃. Change = 0 (not a redox reaction).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Classical and Electronic Concept of Redox and Oxidation Number
As (+3 in As₂S₃) to +5 in H₃AsO₄: change = +2. S (-2 in As₂S₃) to +6 in H₂SO₄: change = +8. S increases more.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Classical and Electronic Concept of Redox and Oxidation Number
Let S = x. Na = +1, O = -2. Equation: 2(+1) + 2x + 3(-2) = 0, 2 + 2x - 6 = 0, 2x = 4, x = +2 (average).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Classical and Electronic Concept of Redox and Oxidation Number
Let S = x. O = -2. Equation: x + 3(-2) = 0, x - 6 = 0, x = +6.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Classical and Electronic Concept of Redox and Oxidation Number
S (0) becomes +4 in SO₂. Change = +4 - 0 = +4.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Classical and Electronic Concept of Redox and Oxidation Number
S (-2 in 5FeS) becomes +6 in 2Fe₂(SO₄)3 (6 S atoms). Total change = 6 × (+6 - (-2)) = 48; per FeS = 48/5 = 9.6, but reaction context gives +8.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Balancing Redox Reactions - Oxidation Number Method and Half Reaction
Let the oxidation number of S be x. H = +1, O = -2. Equation: 2(+1) + x + 4(-2) = 0. Solving: 2 + x - 8 = 0, x = +6.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
