#sulfur

CHEMISTRY

The oxidation state of sulfur in SO_3 is:

Given: The oxidation state of sulfur in SO_3 is: These values define the system as per NCERT data. Formula: In SO_3, O is -2, so 3(-2) + S = 0, S = +6, as sulfur shares electrons with three oxygen atoms.. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

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Isomerism - Stereoisomerism - Geometrical and Optical Isomerism

In Lassaigne’s test, the formation of a blood-red color indicates the presence of which two elements together?

When both nitrogen and sulphur are present, they form NaSCN, which reacts with Fe³⁺ to give a blood-red color (Fe(SCN)₃).

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Isomerism - Stereoisomerism - Geometrical and Optical Isomerism

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Types of Redox Reactions - Combination Decomposition Displacement

What is the oxidation number of sulfur in S₂O₃²⁻?

Let S = x. O = -2. Equation: 2x + 3(-2) = -2, 2x - 6 = -2, 2x = 4, x = +2 (average).

Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Types of Redox Reactions - Combination Decomposition Displacement

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Oxidizing and Reducing Agents and Strength

In the reaction 2Na + S → Na₂S, which species is the oxidizing agent?

The oxidizing agent is reduced. S (0) gains electrons to become S (-2) in Na₂S, oxidizing Na (0 to +1).

Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength

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Electrode Potential and Electrochemical Series and Galvanic Cells

What is the oxidation number of sulfur in H₂S?

Let S = x. H = +1. Equation: 2(+1) + x = 0, 2 + x = 0, x = -2.

Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells

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Electrode Potential and Electrochemical Series and Galvanic Cells

What is the oxidation number of sulfur in S₂O₃²⁻?

Let S = x. O = -2. Equation: 2x + 3(-2) = -2, 2x - 6 = -2, 2x = 4, x = +2 (average).

Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells

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Classical and Electronic Concept of Redox and Oxidation Number

What is the change in oxidation number of sulfur in the reaction SO₂ + H₂O → H₂SO₃?

S (+4 in SO₂) remains +4 in H₂SO₃. Change = 0 (not a redox reaction).

Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Classical and Electronic Concept of Redox and Oxidation Number

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Classical and Electronic Concept of Redox and Oxidation Number

In the reaction As₂S₃ + 7H₂O₂ + 2H₂O → 2H₃AsO₄ + 3H₂SO₄, which element’s oxidation number increases the most?

As (+3 in As₂S₃) to +5 in H₃AsO₄: change = +2. S (-2 in As₂S₃) to +6 in H₂SO₄: change = +8. S increases more.

Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Classical and Electronic Concept of Redox and Oxidation Number

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Classical and Electronic Concept of Redox and Oxidation Number

What is the oxidation number of sulfur in Na₂S₂O₃?

Let S = x. Na = +1, O = -2. Equation: 2(+1) + 2x + 3(-2) = 0, 2 + 2x - 6 = 0, 2x = 4, x = +2 (average).

Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Classical and Electronic Concept of Redox and Oxidation Number

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Classical and Electronic Concept of Redox and Oxidation Number

What is the oxidation number of sulfur in SO₃?

Let S = x. O = -2. Equation: x + 3(-2) = 0, x - 6 = 0, x = +6.

Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Classical and Electronic Concept of Redox and Oxidation Number

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Classical and Electronic Concept of Redox and Oxidation Number

What is the change in oxidation number of sulfur in the reaction S + 2H₂SO₄ → 3SO₂ + 2H₂O?

S (0) becomes +4 in SO₂. Change = +4 - 0 = +4.

Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Classical and Electronic Concept of Redox and Oxidation Number

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Balancing Redox Reactions - Oxidation Number Method and Half Reaction

In 5FeS + 9O₂ → Fe₂O₃ + 2Fe₂(SO₄)3, what is the total change in oxidation number of sulfur per mole of FeS?

S (-2 in 5FeS) becomes +6 in 2Fe₂(SO₄)3 (6 S atoms). Total change = 6 × (+6 - (-2)) = 48; per FeS = 48/5 = 9.6, but reaction context gives +8.

Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Balancing Redox Reactions - Oxidation Number Method and Half Reaction

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