#strong interaction

Radioactive Decay, Nuclear Forces and Stability

Why is the nuclear force considered saturated in large nuclei?

**Stability** belt of stability N≈Z for light, N>Z for heavy due to Coulomb, beyond leads to alpha decay, fission, stability requires balance, nuclear force saturated explains constant density and BE/A. The nuclear force is short-ranged, affecting only a fixed number of neighboring nucleons, so adding more nucleons in large nuclei does not proportionally increase the binding energy, leading to saturation. Using E_n = -13.6/n² eV, r_n = n² a₀, L = n h/2π, R = R₀ A^¹/³, BE = Δm c² and 1 u = 931.5 MeV, evaluation yields Limited range of interaction, consistent with Bohr model and nuclear binding

Ref: NCERT > Physics Book > Atoms and Nuclei > Radioactive Decay, Nuclear Forces and Stability

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Radioactive Decay, Nuclear Forces and Stability

Which of the following best describes the nuclear force?

**Nuclear force** strong, short-range ~1 fm, attractive, charge independent, saturated in large nuclei because each nucleon interacts only with neighbors, not all others, so BE/A saturates ~8 MeV, primary factor limiting stable nuclei size is Coulomb repulsion between protons growing as Z² vs strong force saturating, beyond Z≈83 no stable nuclei, competition between Coulomb and strong. The nuclear force is a strong, short-range attractive force that binds protons and neutrons in the nucleus, overcoming the Coulomb repulsion between protons. It is much stronger than the Coulomb force and does n

Ref: NCERT > Physics Book > Atoms and Nuclei > Radioactive Decay, Nuclear Forces and Stability

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Radioactive Decay, Nuclear Forces and Stability

Which of the following forces is negligible in holding the nucleus together?

**Nuclear force** strong, short-range ~1 fm, attractive, charge independent, saturated in large nuclei because each nucleon interacts only with neighbors, not all others, so BE/A saturates ~8 MeV, primary factor limiting stable nuclei size is Coulomb repulsion between protons growing as Z² vs strong force saturating, beyond Z≈83 no stable nuclei, competition between Coulomb and strong. The gravitational force is much weaker than the nuclear force and Coulomb force, playing a negligible role in binding nucleons within the tiny nuclear volume, where the strong nuclear force dominates. Using E_n

Ref: NCERT > Physics Book > Atoms and Nuclei > Radioactive Decay, Nuclear Forces and Stability

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Radioactive Decay, Nuclear Forces and Stability

Which statement best describes the nuclear force at distances greater than 0.8 fm?

**Nuclear force** strong, short-range ~1 fm, attractive, charge independent, saturated in large nuclei because each nucleon interacts only with neighbors, not all others, so BE/A saturates ~8 MeV, primary factor limiting stable nuclei size is Coulomb repulsion between protons growing as Z² vs strong force saturating, beyond Z≈83 no stable nuclei, competition between Coulomb and strong. At distances greater than 0.8 fm, the nuclear force is attractive and dominates over the Coulomb force, binding nucleons together until it drops off rapidly beyond a few femtometres. Using E_n = -13.6/n² eV, r_n

Ref: NCERT > Physics Book > Atoms and Nuclei > Radioactive Decay, Nuclear Forces and Stability

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Radioactive Decay, Nuclear Forces and Stability

Which characteristic of the nuclear force explains its dominance over the Coulomb force in the nucleus?

**Nuclear force** strong, short-range ~1 fm, attractive, charge independent, saturated in large nuclei because each nucleon interacts only with neighbors, not all others, so BE/A saturates ~8 MeV, primary factor limiting stable nuclei size is Coulomb repulsion between protons growing as Z² vs strong force saturating, beyond Z≈83 no stable nuclei, competition between Coulomb and strong. The nuclear force is much stronger than the Coulomb force at short distances (within the nucleus), allowing it to overcome proton repulsion and bind nucleons together. Using E_n = -13.6/n² eV, r_n = n² a₀, L = n

Ref: NCERT > Physics Book > Atoms and Nuclei > Radioactive Decay, Nuclear Forces and Stability

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Radioactive Decay, Nuclear Forces and Stability

What happens to the nuclear force when nucleons are separated by more than a few femtometres?

**Nuclear force** strong, short-range ~1 fm, attractive, charge independent, saturated in large nuclei because each nucleon interacts only with neighbors, not all others, so BE/A saturates ~8 MeV, primary factor limiting stable nuclei size is Coulomb repulsion between protons growing as Z² vs strong force saturating, beyond Z≈83 no stable nuclei, competition between Coulomb and strong. The nuclear force is short-ranged and drops rapidly to zero beyond a few femtometres, leaving only weaker forces like Coulomb repulsion or gravity to act between nucleons. Using E_n = -13.6/n² eV, r_n = n² a₀, L

Ref: NCERT > Physics Book > Atoms and Nuclei > Radioactive Decay, Nuclear Forces and Stability

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