Two hollow spherical conductors of different radii are charged with the same amount of charge and then connected by a th
**Spherical conductor** behaves as point charge outside, potential V = k Q/R at surface, field E = k Q/r² for r>R, zero inside for rR, so E = k Q/r² =9×10⁹×6×10⁻⁸/0.16=3375 N/C. When two conductors are connected by a wire, they reach the same potential. The potential on the surface of a spherical conductor is given by V = (Q/4 π ε₀ R) , where Q is the charge and R is the radius. If the radii are different, say R₁ and R₂ , and initially both have charge Q , after connection, V₁
Ref: NCERT > Physics Book > Electrostatic Potential and Capacitance > Electric Potential and Potential Difference
