What is the molality of a solution containing 16 g of sorbitol (molar mass = 182 g/mol) in 800 g of water?
Moles of sorbitol = (16/182) ≈ 0.0879 mol . Mass of solvent = 800 g = 0.8 kg. Molality = (0.0879/0.8) ≈ 0.1099 mol/kg .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law