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#solid sphere

14 public questions tagged with this topic.

A solid sphere of mass 2kg and radius 0.6m rotates about its center at 5rad/s. What is its rotational kinetic energy?

I = 25MR2 = 25×2×(0.6)2 = 0.288kg m2. K = 12Iω2 = 12×0.288×(5)2 = 0.144×25 = 3.6J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.6 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 6kg and radius 0.4m has an angular momentum of 11.52kg m2/s. What is its angular velocity?

I = 25MR2 = 25×6×(0.4)2 = 0.384kg m2. ω = LI = 11.520.384 = 30rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 30 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 5kg and radius 0.2m has an angular momentum of 8kg m2/s. What is its angular velocity?

I = 25MR2 = 25×5×(0.2)2 = 0.08kg m2. ω = LI = 80.08 = 100rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 100 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 5kg and radius 0.3m rotates about an axis through its center. If its angular momentum is 9kg m2/s

L = Iω. For a sphere: I = 25MR2 = 25×5×(0.3)2 = 0.18kg m2. ω = LI = 90.18 = 50rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 50 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 3kg and radius 0.4m has an angular momentum of 12kg m2/s. What is its angular velocity?

I = 25MR2 = 25×3×(0.4)2 = 0.192kg m2. ω = LI = 120.192≈62.5rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 62.5 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 3kg and radius 0.4m rotates about its center at 5rad/s. What is its rotational kinetic energy?

I = 25MR2 = 25×3×(0.4)2 = 0.192kg m2. K = 12Iω2 = 12×0.192×(5)2 = 0.096×25 = 2.4J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.4 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 1kg and radius 0.8m has a kinetic energy of 12.8J. What is its angular speed?

I = 25MR2 = 25×1×(0.8)2 = 0.256kg m2. K = 12Iω2⇒12.8 = 12×0.256×ω2⇒25.6 = 0.256ω2⇒ω2 = 100⇒ω = 10rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 3kg and radius 0.2m rotates at 15rad/s. What is its angular momentum about its axis?

I = 25MR2 = 25×3×(0.2)2 = 0.048kg m2. L = Iω = 0.048×15 = 0.72kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.72 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 4kg and radius 0.3m has an angular momentum of 7.2kg m2/s. What is its angular velocity?

I = 25MR2 = 25×4×(0.3)2 = 0.144kg m2. ω = LI = 7.20.144 = 50rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 50 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 2kg and radius 0.1m has an angular momentum of 4kg m2/s about its axis. What is its angular veloc

L = Iω. For a sphere: I = 25MR2 = 25×2×(0.1)2 = 0.008kg m2. ω = LI = 40.008 = 500rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 500 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 5kg and radius 0.2m rotates at 10rad/s. What is its angular momentum about its axis?

I = 25MR2 = 25×5×(0.2)2 = 0.08kg m2. L = Iω = 0.08×10 = 0.8kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.8 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 1kg and radius 0.5m has a kinetic energy of 5J. What is its angular speed?

I = 25MR2 = 25×1×(0.5)2 = 0.1kg m2. K = 12Iω2⇒5 = 12×0.1×ω2⇒10 = 0.1ω2⇒ω2 = 100⇒ω = 10rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.