11 public questions tagged with this topic.
I = 12MR2 = 12×4×(0.2)2 = 0.08kg m2. L = Iω = 0.08×25 = 2kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.0 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 12MR2 = 12×2×(0.5)2 = 0.25kg m2. K = 12Iω2⇒10 = 12×0.25×ω2⇒20 = 0.25ω2⇒ω2 = 80⇒ω = 80≈8.94rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 8.94 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 12MR2 = 12×3×(0.4)2 = 0.24kg m2. ω = LI = 120.24 = 50rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 50 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 12MR2 = 12×2×(0.1)2 = 0.01kg m2. K = 12Iω2 = 12×0.01×(20)2 = 0.005×400 = 2J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.0 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 12MR2 = 12×5×(0.5)2 = 0.625kg m2. ω = LI = 12.50.625 = 20rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 20 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 12MR2 = 12×4×(0.3)2 = 0.18kg m2. K = 12Iω2 = 12×0.18×(6)2 = 0.09×36 = 3.24J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.24 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
v = ωr. ω = 4rad/s, r = 0.5m. v = 4×0.5 = 2m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.0 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 12MR2 = 12×4×(0.5)2 = 0.5kg m2. K = 12Iω2⇒50 = 12×0.5×ω2⇒100 = 0.5ω2⇒ω2 = 200⇒ω = 200≈14.14rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 14 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 12MR2 = 12×3×(0.1)2 = 0.015kg m2. K = 12Iω2⇒4.5 = 12×0.015×ω2⇒9 = 0.015ω2⇒ω2 = 600⇒ω = 600≈24.5rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 24.5 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 12MR2 = 12×3×(0.5)2 = 0.375kg m2. L = Iω = 0.375×7 = 2.625kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.625 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 12MR2 = 12×6×(0.3)2 = 0.27kg m2. ω = LI = 10.80.27 = 40rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 40 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
