A pure Si crystal is doped with 1 ppm of pentavalent impurity. If the Si atom density is \( 5 \times 10^{28} \, \text{m}
**Charge carriers** in n-type majority electrons, minority holes, in p-type majority holes, minority electrons, minority concentration reduced due to recombination n_e n_h = n_i², doping increases majority, conductivity σ = e(n_e μ_e + n_h μ_h), increases with doping. Donor ionization energy small ~0.01 eV, electrons easily promoted to conduction band at room temperature. 1 ppm = 1 part per million = 10⁻⁶ . Number of donor atoms = 10⁻⁶ × 5 × 10²⁸ = 5 × 10²² m⁻³ . These contribute electrons, assuming full ionization at room temperature. Substituting values gives 5 × 10²² m⁻³, which matches expe
Ref: NCERT > Physics Book > Electronic Devices > Doping, Charge Carriers and Conductivity