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#second minimum

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Diffraction - Single-Slit and Central Maximum

What is the angular position of the second minimum in a single-slit diffraction pattern if the slit width is \( 2.0 \, \

**Diffraction bending** property of light waves causes bending around corners, width of central maximum inversely proportional to slit width, intensity of secondary maxima decreases with order because less constructive interference, angular position of minima θ_n = n λ/a, n=±1,±2..., second minimum n=2, third n=3, condition for third secondary maximum approx a sinθ = (2n+1)λ/2. Minima occur at sin θ = (nλ/a) . For the second minimum, n = 2 . λ = 4.0 × 10⁻⁷ m , a = 2.0 × 10⁻⁶ m . sin θ = (2 × 4.0 × 10⁻⁷/2.0 × 10⁻⁶) = 0.4 , θ = sin⁻¹(0.4) ≈ 23.6° . Using Δ

Ref: NCERT > Physics Book > Wave Optics > Diffraction - Single-Slit and Central Maximum

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Diffraction - Single-Slit and Central Maximum

What is the angular position of the second minimum in a single-slit diffraction pattern if the slit width is \( 8.0 \, \

**Single-slit diffraction** central maximum width W =2λ D/a, a slit width, D distance, angular width θ =2λ/a, first minimum at a sinθ = λ, fourth minimum a sinθ=4λ, sinθ=4λ/a, for a=5.0 μm λ=500 nm sinθ=4×0.5/5=0.4 θ≈23.6°, central maximum width increases when slit width reduced to half doubles width, when wavelength quadrupled width quadruples, when slit tripled width one-third. Minima occur at sin θ = (nλ/a) . For the second minimum, n = 2 . λ = 6.4 × 10⁻⁷ m , a = 8.0 × 10⁻⁶ m . sin θ = (2 × 6.4 × 10⁻⁷/8.0 × 10⁻⁶) = 0.16 , θ = sin⁻¹(0.16) ≈

Ref: NCERT > Physics Book > Wave Optics > Diffraction - Single-Slit and Central Maximum

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Diffraction - Single-Slit and Central Maximum

What is the angular position of the second minimum in a single-slit diffraction pattern if the slit width is \( 3.0 \, \

**Single-slit diffraction** central maximum width W =2λ D/a, a slit width, D distance, angular width θ =2λ/a, first minimum at a sinθ = λ, fourth minimum a sinθ=4λ, sinθ=4λ/a, for a=5.0 μm λ=500 nm sinθ=4×0.5/5=0.4 θ≈23.6°, central maximum width increases when slit width reduced to half doubles width, when wavelength quadrupled width quadruples, when slit tripled width one-third. Minima occur at sin θ = (nλ/a) . For the second minimum, n = 2 . λ = 6.0 × 10⁻⁷ m , a = 3.0 × 10⁻⁶ m . sin θ = (2 × 6.0 × 10⁻⁷/3.0 × 10⁻⁶) = 0.4 , θ = sin⁻¹(0.4) ≈

Ref: NCERT > Physics Book > Wave Optics > Diffraction - Single-Slit and Central Maximum

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