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#seawater density

2 public questions tagged with this topic.

What is the gauge pressure at a depth of 3.5m in seawater (ρ\=1.03×103kg/m3)? (Take g\=10m/s2)

Gauge pressure: Pg = ρgh. ρ = 1.03×103kg/m3, g = 10m/s2, h = 3.5m. Pg = 1.03×103×10×3.5 = 3.605×104Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.6 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

A manometer with seawater (ρ\=1.03×103kg/m3) shows a height difference of 0.19m. What is the pressure difference? (Take

ΔP = ρgh. ρ = 1.03×103kg/m3, g = 10m/s2, h = 0.19m. ΔP = 1.03×103×10×0.19 = 1957Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1957 Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.