13 public questions tagged with this topic.
I = 25MR2 = 25×2×(0.6)2 = 0.288kg m2. K = 12Iω2 = 12×0.288×(5)2 = 0.144×25 = 3.6J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.6 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = MR2 = 3×(0.4)2 = 0.48kg m2. K = 12Iω2 = 12×0.48×(5)2 = 0.24×25 = 6J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 6.0 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Rotational KE: K = 12Iω2. Moment of inertia of a disk: I = 12MR2 = 12×2×(0.2)2 = 0.04kg m2. K = 12×0.04×(10)2 = 0.02×100 = 2J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 25MR2 = 25×3×(0.4)2 = 0.192kg m2. K = 12Iω2 = 12×0.192×(5)2 = 0.096×25 = 2.4J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.4 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
KE: K = 12Iω2. For a ring: I = MR2 = 1×(0.2)2 = 0.04kg m2. 4 = 12×0.04×ω2⇒8 = 0.04ω2⇒ω2 = 200⇒ω = 200≈14.14rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 14 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = MR2 = 5×(0.2)2 = 0.2kg m2. K = 12Iω2 = 12×0.2×(10)2 = 0.1×100 = 10J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 12MR2 = 12×2×(0.1)2 = 0.01kg m2. K = 12Iω2 = 12×0.01×(20)2 = 0.005×400 = 2J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.0 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Rotational kinetic energy K = 12Iω2 depends on ω2. Halving ω reduces ω2 to 14, so K becomes one-fourth its original value. As per NCERT, applying relevant law/formula with correct units and sign convention leads to It becomes one-fourth. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 12MR2 = 12×4×(0.3)2 = 0.18kg m2. K = 12Iω2 = 12×0.18×(6)2 = 0.09×36 = 3.24J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.24 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = MR2 = 4×(0.3)2 = 0.36kg m2. K = 12Iω2 = 12×0.36×(8)2 = 0.18×64 = 11.52J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 11.52 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Rotational kinetic energy is given by K = 12Iω2, depending on moment of inertia and angular velocity, not linear velocity directly. As per NCERT, applying relevant law/formula with correct units and sign convention leads to K\=12Iω2. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = 25MR2 = 25×1×(0.2)2 = 0.016kg m2. K = 12Iω2 = 12×0.016×(10)2 = 0.008×100 = 0.8J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.8 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
