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#rotational dynamics

21 public questions tagged with this topic.

A wheel with moment of inertia 6kg m2 rotates at 3rad/s. A torque of 12Nm acts for 3s. What is its final angular velocit

α = τI = 126 = 2rad/s2. Δω = αt = 2×3 = 6rad/s. ω = ω0+Δω = 3+6 = 9rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 9 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 5kg and radius 0.3m rotates about an axis through its center. If its angular momentum is 9kg m2/s

L = Iω. For a sphere: I = 25MR2 = 25×5×(0.3)2 = 0.18kg m2. ω = LI = 90.18 = 50rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 50 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

Why does a symmetric body rotating about its symmetry axis have angular momentum aligned with the axis?

Symmetry ensures perpendicular components of angular momentum cancel out, leaving L = Iω aligned with the axis of rotation. As per NCERT, applying relevant law/formula with correct units and sign convention leads to Due to cancellation of perpendicular components. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

Which statement is true about the axis of rotation in pure rotational motion?

In pure rotational motion, the axis of rotation is fixed, meaning it does not move or change direction, constraining the body to rotate about it. As per NCERT, applying relevant law/formula with correct units and sign convention leads to It is always fixed. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A disk with moment of inertia 1.5kg m2 rotates at 4rad/s. A torque of 6Nm acts for 3s. What is its final angular velocit

α = τI = 61.5 = 4rad/s2. Δω = αt = 4×3 = 12rad/s. ω = ω0+Δω = 4+12 = 16rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 16 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A wheel of radius 0.4m and moment of inertia 1.6kg m2 is accelerated by a torque of 8Nm. What is its angular acceleratio

Torque: τ = Iα. τ = 8Nm, I = 1.6kg m2. α = τI = 81.6 = 5rad/s2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5 rad/s². This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

Why does a body with zero net torque maintain its rotational state?

Zero net torque (τ = 0) means no change in angular momentum (dLdt = 0), so the rotational state (angular velocity) remains constant. As per NCERT, applying relevant law/formula with correct units and sign convention leads to Due to no change in angular momentum. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

In rotational dynamics, what role does torque play?

Torque causes angular acceleration, as per τ = Iα, analogous to how force causes linear acceleration in Newton’s second law. As per NCERT, applying relevant law/formula with correct units and sign convention leads to It causes angular acceleration. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 4kg and radius 0.3m has an angular momentum of 7.2kg m2/s. What is its angular velocity?

I = 25MR2 = 25×4×(0.3)2 = 0.144kg m2. ω = LI = 7.20.144 = 50rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 50 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A cylinder of mass 10kg and radius 0.5m rolls without slipping. If its angular momentum about its axis is 25kg m2/s, wha

Angular momentum: L = Iω. For a solid cylinder: I = 12MR2 = 12×10×(0.5)2 = 1.25kgm2. ω = LI = 251.25 = 20rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 20 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.