In a circuit with two resistors of different resistances in series, which resistor dissipates more power if the same cur
**Resistance** R = ρ l/A, ρ resistivity (Ω·m), l length (m), A area (m²), ρ = m/(n e² τ) from Drude model, τ average collision time. Ohm's law V = I R holds when ρ constant, independent of V. Volume constant stretching l→2l implies A→A/2, so R' = ρ·2l/(A/2)=4R, resistance quadruples when length doubles at constant volume. Power P = I² R . With the same current ( I ) in series, power is proportional to resistance ( R ). The resistor with higher resistance dissipates more power. Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0,
Ref: NCERT > Physics Book > Current Electricity > Resistance, Resistivity and Ohm's Law