#redox chemistry

CHEMISTRY

How many electrons are involved in the reduction of 1 mol of Cu²⁺ to Cu(s)?

Given: How many electrons are involved in the reduction of 1 mol of Cu²⁺ to Cu(s)? Formula: Reaction: Cu²+ + 2e- -> Cu(s). Substitution & Calculation: 2 electrons are required per mole of Cu²⁺. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

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CHEMISTRY

In 2KMnO₄ + 16H₂SO₄ + 10NaCl -> 5Cl₂ + 2MnSO₄ + 8H₂O + 5Na₂SO₄ + K₂SO₄, which species is reduced?

Mn (+7 in KMnO₄ to +2 in MnSO₄ ) is reduced, while Cl (-1 to 0 in Cl₂ ) is oxidized. This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

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Oxidizing and Reducing Agents and Strength

Which reaction involves a redox process where the oxidizing agent contains a halogen?

In 2Fe + 3I₂ → 2FeI₃, I₂ (I: 0 to -1) is reduced, oxidizing Fe (0 to +3).

Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength

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Balancing Redox Reactions - Oxidation Number Method and Half Reaction

What is the oxidation number of nitrogen in NO₂?

Let N = x. O = -2. Equation: x + 2(-2) = 0, x - 4 = 0, x = +4.

Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Balancing Redox Reactions - Oxidation Number Method and Half Reaction

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