In an AC circuit with a series combination of resistor, inductor, and capacitor, what is the condition for the circuit t
**Condition for resistive behavior** X_L = X_C, so ωL=1/ωC, ω²=1/LC, this is resonance, impedance purely resistive Z=R, current maximum, power maximum P= V²/R, inductive and capacitive reactances equal magnitude opposite sign cancel, circuit appears resistive. For an LCR series circuit to be purely resistive, the net reactance must be zero ( X_L - X_C = 0 ), which occurs at resonance when X_L = X_C . This makes the impedance equal to the resistance ( Z = R ), and the circuit behaves as if only resistance is present. Applying X_L = ωL, X_C = 1/ωC, Z = √(R² + (X_L - X_C)²), I_rms =
Ref: NCERT > Physics Book > Alternating Currents > Resonance in LCR Circuit and Q-Factor