3 public questions tagged with this topic.
We can see that using formula we get P(x; μ) = (e-μ) (μx) / x!. Calculation gives this directly, check steps: apply rule, substitute values, simplify to get P(x; μ) = (e-μ) (μx) / x!.
Ref: NCERT Mathematics Class XII — Probability
Let's break it down: solving fully: apply relevant formula, put numbers, compute. Result comes as binomial distribution. Easy verification shows it satisfies condition.
Ref: NCERT Mathematics Class XI and XII
In easy words, binomial needs fixed n, independent trials, P=nCr p^r q^(n-r), mean=np, variance=npq, mode floor((n+1)p). Complete properties.
Ref: NCERT Mathematics Class XII — Probability
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