The critical angle of a certain medium is \({\sin ^{ - 1}}\left( {\frac{3}{5}} \right)\). The polarizing angle of the me
μ=1/sinC=5/3, Brewster angle tanIp=μ => Ip=tan^-1(5/3).
Ref: NCERT Physics Class 12 Chapter 10 Wave Optics
#polarizing angle
1 public question tagged with this topic.
