For N₂O₄(g) 2NO₂(g) , Kp = 0.16 at 400 K. If 0.5 moles of N₂O₄ are placed in a 1 L vessel, what is PNO₂ at equilibrium (
Initial: PN₂O₄ = (0.5 × 0.0831 × 400/1) = 16.62 bar . Let 2x = PNO₂ , PN₂O₄ = 16.62 - x , total pressure = 16.62 + x . Kp = ((PNO₂)²/PN₂O₄) = ((2x)²/16.62 - x) = 0.16 , 4x² = 0.16 (16.62 - x) , x ≈ 0.8 , PNO₂ = 1.6 bar .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Relationship Between Kp Kc and Factors Affecting Equilibrium - Le Chatelier
