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#plant molecular biology

10 public questions tagged with this topic.

T-DNA transfer initiates at:

Ti plasmid T-DNA is delimited by two imperfect 25 base pair direct repeats designated right and left borders. Transfer is inherently polar because right border contains optimal nick site plus adjacent overdrive sequence that recruits VirC1 and VirD2 complex. Nicking at right border creates free 5' end that remains capped by VirD2 and defines leading end for Type IV secretion. Displacement synthesis then proceeds toward left border, which functions merely as termination point. Mutants lacking right border are completely avirulent, while left border deletion still allows transfer with vector bac

Ref: NCERT Biology Class XII Principles on Klenow fill-in labeling, Lehninger Chapter 9 DNA cloning techniques, and Molecular Cloning by Sambrook Chapter 10 documenting end-labeling of cohesive termini.

TRY gene functions as:

The right choice is B: Negative regulator of trichomes. In Jasmonic acid, that matches how the process or concept actually works — the other choices mix up related ideas or use the wrong mechanism. Skip these: A) Positive regulator of trichomes; C) JA receptor; D) JA enzyme. A quick check: if an option needs energy, pumps, or the opposite direction of movement, ask whether that really applies.

Ref: Best CSIR NET Plant Physiology books: Master Unit 6 with Taiz & Zeiger and Salisbury & Ross. Crack Part C experimental questions with top textbooks.

GL1, GL3, and TTG1 together form:

That points to B: Activation complex. Compared with the other options, Activation complex is the one that correctly describes the Jasmonic acid concept. The wrong ones are A) Repressor complex; C) SCF complex; D) MAPK complex. If you’re stuck, eliminate anything that contradicts a basic fact you already know for this topic.

Ref: Best CSIR NET Plant Physiology books: Master Unit 6 with Taiz & Zeiger and Salisbury & Ross. Crack Part C experimental questions with top textbooks.

JAZ proteins function as:

Go with C — Repressors of JA signaling. Under Jasmonic acid, this is the standard explanation you’d use in class: it names the real driver or definition, while the rest are nearby but wrong. Not these: A) Transcription activators; B) Hormone receptors; D) Enzymes. When two options sound similar, choose the one that matches the textbook definition most tightly.

Ref: Best CSIR NET Plant Physiology books: Master Unit 6 with Taiz & Zeiger and Salisbury & Ross. Crack Part C experimental questions with top textbooks.

COI1 is a component of which complex?

SCF ubiquitin ligase (B) is correct here. This is core Jasmonic acid: once you know the definition or pathway step, SCF ubiquitin ligase is the clear fit. The wrong ones are A) APC; C) RNA polymerase; D) Proteasome core. If the topic is about gradients or potentials, water/solutes move from higher to lower of the relevant quantity.

Ref: Best CSIR NET Plant Physiology books: Master Unit 6 with Taiz & Zeiger and Salisbury & Ross. Crack Part C experimental questions with top textbooks.

In Arabidopsis, the major flowering repressor responsible for vernalization requirement is:

Answer: C) FLC. For VERNALIZATION & FLOWERING, remember the key idea and you’ll land on this option; the distractors usually swap cause and effect or confuse similar terms. Avoid: A) FT; B) SOC1; D) FD. Name the process first, then pick the option that describes it — don’t reverse cause and effect.

Ref: Best CSIR NET Plant Physiology books: Master Unit 6 with Taiz & Zeiger and Salisbury & Ross. Crack Part C experimental questions with top textbooks.

CONSTANS (CO) gene is involved in:

The right choice is B: Promotion of flowering in long days. In PHOTOPERIODISM, that matches how the process or concept actually works — the other choices mix up related ideas or use the wrong mechanism. Skip these: A) Inhibition of flowering; C) Seed germination; D) Dormancy. A quick check: if an option needs energy, pumps, or the opposite direction of movement, ask whether that really applies.

Ref: Best CSIR NET Plant Physiology books: Master Unit 6 with Taiz & Zeiger and Salisbury & Ross. Crack Part C experimental questions with top textbooks.

Class D genes mainly control development of:

B fits best: Ovules. Keep the ABCE & ABCDE MODEL +Synapdrgon flowering basics straight and Ovules stands out as the precise answer. Avoid: A) Carpels; C) Stamens; D) Petals. Light and flowering items often hinge on which photoreceptor or day-length rule is in play.

Ref: Best CSIR NET Plant Physiology books: Master Unit 6 with Taiz & Zeiger and Salisbury & Ross. Crack Part C experimental questions with top textbooks.

Tetramers in Quartet model are formed by association of:

The right choice is B: Two dimers. In ABCE & ABCDE MODEL +Synapdrgon flowering, that matches how the process or concept actually works — the other choices mix up related ideas or use the wrong mechanism. Skip these: A) Four monomers; C) Three dimers; D) Five monomers. A quick check: if an option needs energy, pumps, or the opposite direction of movement, ask whether that really applies.

Ref: Best CSIR NET Plant Physiology books: Master Unit 6 with Taiz & Zeiger and Salisbury & Ross. Crack Part C experimental questions with top textbooks.

In Quartet model, functional unit regulating organ identity is:

Answer: C) Tetramer. For ABCE & ABCDE MODEL +Synapdrgon flowering, remember the key idea and you’ll land on this option; the distractors usually swap cause and effect or confuse similar terms. Avoid: A) Monomer; B) Dimer; D) Pentamer. Name the process first, then pick the option that describes it — don’t reverse cause and effect.

Ref: Best CSIR NET Plant Physiology books: Master Unit 6 with Taiz & Zeiger and Salisbury & Ross. Crack Part C experimental questions with top textbooks.