Skip to content

#Photon

7 public questions tagged with this topic.

A photon’s energy is 3.0 eV . What is its momentum? (Take c = 3 × 10⁸ m/s, 1 eV = 1.6 × 10⁻¹⁹ J )

Given: A photon’s energy is 3.0 eV . What is its momentum? (Take c = 3 × 10⁸ m/s, 1 eV = 1.6 × 10⁻¹⁹ J ) These values define the system as per NCERT data. Formula: E = 3.0 × 1.6 × 10⁻¹⁹= 4.8 × 10⁻¹⁹ J. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: For a photon, p = E/c = frac4.8 × 10⁻¹⁹³ × 10⁸= 1.6 × 10⁻²⁷ kg m/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Laws of Motion, Work Energy Power, Gravitation and System of Particles, Topic: Newton's laws, work-energy theorem and rotational dynamics.

A photon has an energy of 5.0 × 10⁻¹⁹J . What is its frequency? (Take h = 6.63 × 10⁻³⁴J s )

Given: A photon has an energy of 5.0 × 10⁻¹⁹J . What is its frequency? (Take h = 6.63 × 10⁻³⁴J s ) These values define the system as per NCERT data. Formula: E = h v. This is standard NCERT relation. Substitution & Calculation: v = E/h = frac5.0 × 10⁻¹⁹⁶.63 × 10⁻³⁴approx 7.54 × 10¹⁴Hz . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Relevant Physics topic covering fundamental principles,