The oxidation state of phosphorus in P_4O_{10 is:
Given: The oxidation state of phosphorus in P_4O_{10 is: These values define the system as per NCERT data. Formula: In P_4O_{10, O is -2, so 4P + 10(-2) = 0, 4P - 20 = 0, 4P = 20, P = +5, as P shares electrons with oxygen.. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.