What is the oxidation number of chlorine in HClO₄?
Let Cl = x. H = +1, O = -2. Equation: +1 + x + 4(-2) = 0, 1 + x - 8 = 0, x = +7.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
#perchloric acid
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