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#particle speed

11 public questions tagged with this topic.

Acceleration and Velocity Analysis

A particle moves in the x-y plane with a constant acceleration of (2 î + 3 ĵ) m/s². If it starts from rest at the origin

Velocity is given by v = v₀ + at, where v₀ = 0 (starts from rest). As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 7.21 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Acceleration and Velocity Analysis - Part 8

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Acceleration and Velocity Analysis

A particle starts from rest with a constant acceleration of (4 î + 2 ĵ) m/s². What is its speed after 5 s?

Velocity v = v₀ + at, where v₀ = 0. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 10 m/s as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Acceleration and Velocity Analysis - Part 8

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Acceleration and Velocity Analysis

A particle’s position is given by x\=4t2−t and y\=2t+t2 (in meters and seconds). What is its speed at t\=1s?

Velocity: vx=dxdt=8t−1,vy=dydt=2+2t. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 6 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Acceleration and Velocity Analysis - Part 8

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Equations of Motion and Problem Solving

A particle’s position is given by x\=2t+t2 and y\=3t−2t2 (in meters and seconds). What is its speed at t\=2s?

Velocity: vx=dxdt=2+2t,vy=dydt=3−4t. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 6 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Equations of Motion and Problem Solving

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Equations of Motion and Problem Solving

A particle’s position is given by x\=3t2−4t and y\=5t (in meters and seconds). What is its speed at t\=1s?

Velocity: vx=dxdt=6t−4,vy=dydt=5. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 4 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Equations of Motion and Problem Solving

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