10 public questions tagged with this topic.
Recall the rule after simplifying, -2 < k < 2 is left. The method is simple: formula → substitution → calculation → answer.
Ref: NCERT Mathematics Class XI — Sets, Relations and Functions
Think of it like this: solving fully: apply relevant formula, put numbers, compute. Result comes as 7. Easy verification shows it satisfies condition.
Ref: NCERT Mathematics Class XI and XII
The logic is straightforward: using formula we get k ≠ 1 and k ≠ -2. Calculation gives this directly, check steps: apply rule, substitute values, simplify to get k ≠ 1 and k ≠ -2.
Ref: NCERT Mathematics Class XII — Matrices and Determinants
Recall the rule using formula we get k = 4. Calculation gives this directly, check steps: apply rule, substitute values, simplify to get k = 4.
Ref: NCERT Mathematics Class XII — Matrices and Determinants
Here's the idea in simple terms: after simplifying, 2 is left. The method is simple: formula → substitution → calculation → answer.
Ref: NCERT Mathematics Class XII — Applications of Derivatives
Recall the rule f'=3x²+2x+k. No extremum means f'=0 has no real root. Discriminant D=4-12k1/3. Complete.
Ref: NCERT Mathematics Class XII — Applications of Derivatives
Simply put, after simplifying, k < 2 is left. The method is simple: formula → substitution → calculation → answer.
Ref: NCERT Mathematics Class XII — Applications of Derivatives
The trick is complete solution: write formula, plug data, do arithmetic. Final value matches - 2. Simple and accurate.
Ref: NCERT Mathematics Class XII — Matrices and Determinants
The trick is complete solution: write formula, plug data, do arithmetic. Final value matches k = 2. Simple and accurate.
Ref: NCERT Mathematics Class XII — Matrices and Determinants
Applying the basic concept, after simplifying, 21±16110 is left. The method is simple: formula → substitution → calculation → answer.
Ref: NCERT Mathematics Class XII — Matrices and Determinants
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