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#optics explanation

2 public questions tagged with this topic.

Diffraction - Single-Slit and Central Maximum

Why does the diffraction pattern of a single slit show a central maximum broader than its secondary maxima?

**Diffraction bending** property of light waves causes bending around corners, width of central maximum inversely proportional to slit width, intensity of secondary maxima decreases with order because less constructive interference, angular position of minima θ_n = n λ/a, n=±1,±2..., second minimum n=2, third n=3, condition for third secondary maximum approx a sinθ = (2n+1)λ/2. The central maximum results from constructive interference of all secondary wavelets in phase, while secondary maxima involve partial cancellations, reducing their width and intensity. Using Δ = d sinθ, y = n λ D/d, a s

Ref: NCERT > Physics Book > Wave Optics > Diffraction - Single-Slit and Central Maximum

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Reflection by Spherical Mirrors and Mirror Formula

Why does the image formed by a convex lens become real and inverted when the object is moved beyond the focal point?

**Concave mirror image formation** depends on object position: beyond C real inverted diminished between F and C, at C real inverted same size at C, between C and F real inverted magnified beyond C, at F image at infinity, within F virtual erect magnified behind mirror. Beyond the focal point, a convex lens converges light rays to a point on the opposite side of the lens. This convergence forms a real image, and because the rays cross over, the image is inverted relative to the object’s orientation. Substituting values gives Due to convergence of rays on the opposite side, which matches expect

Ref: NCERT > Physics Book > Ray Optics > Reflection by Spherical Mirrors and Mirror Formula

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