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α = (Lambdam/Lambdam°) = (120/126.5) = 0.9486 ≈ 0.95 .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
α = (Lambdam/Lambdam°) = (120/126.5) = 0.9486 ≈ 0.95 .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
25 ppm = 25 g NaNO₃ in 10⁶ g solution. Volume = 1000 L. Moles = 25/85 ≈ 0.2941 mol; molarity = 0.2941/1000 ≈ 2.941 × 10⁻⁴ M.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Concentration Terms - Molarity Molality and Mole Fraction
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