During electrolysis of aqueous NaI with inert electrodes, 0.224 L of H₂ (STP) is produced at the cathode. How many coulo
Cathode: 2H₂O + 2e⁻ → H₂ + 2OH⁻ . Moles = (0.224/22.4) = 0.01 mol , Charge = 0.01 × 2 × 96500 = 1930 C .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Electrolytic Cells and Electrolysis and Faraday's Laws
