If for a binomial distribution n = 5 and 3P(X = 2) = P(X = 3), the probability of success is
In easy words, 3·5C2 p²q³=5C3 p³q², so 30q=10p, 3(1-p)=p, 3-3p=p, p=3/4. Complete solving.
Ref: NCERT Mathematics Class XII — Probability
#n=5
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